A py file can also build Django applications

DeanWu 2020-11-16 12:52:32
py file build django applications

In use today vue Framework development system , Back end interface is needed , But the interface hasn't been developed yet . I want to use the simplest way to build a minimalist API service , Because I prefer Django frame , I wonder if I can use Django The framework is simple to build Flask A single file like that web service . Sure enough , I found , Excerpts to share with you .

# app.py
import os
import sys
from dataclasses import dataclass
from django.conf import settings
from django.core.wsgi import get_wsgi_application
from django.http import HttpResponseRedirect, JsonResponse
from django.urls import path
from django.utils.crypto import get_random_string
# django Configuration file for , amount to settings.py The configuration file , You can add and delete... Directly here
# The bottom is already the simplest Django Start the required parameters
DEBUG=(os.environ.get("DEBUG", "") == "1"),
ALLOWED_HOSTS=["*"], # Disable host header validation
ROOT_URLCONF=__name__, # Make this module the urlconf
), # We aren't using any security features but Django requires this setting
# Use dataclass The decorator simulates model.
class Character:
name: str
age: int
def as_dict(self, id_):
return {
"id": id_,
"name": self.name,
"age": self.age,
# List data , You can use fields directly to construct the data to be returned
characters = {
1: Character("Rick Sanchez", 70),
2: Character("Morty Smith", 14),
# Django View part , For convenience, simple and direct use function base view
def index(request):
return HttpResponseRedirect("/characters/")
def characters_list(request):
return JsonResponse(
{"data": [character.as_dict(id_) for id_, character in characters.items()]}
def characters_detail(request, character_id):
character = characters[character_id]
except KeyError:
return JsonResponse(
data={"error": f"Character with id {character_id!r} does not exist."},
return JsonResponse({"data": character.as_dict(character_id)})
# Django route part , Same as url.py
urlpatterns = [
path("", index),
path("characters/", characters_list),
path("characters/<int:character_id>/", characters_detail),
# structure uwsgi Use application You can use uwsgi etc. WSGI Software startup of the protocol .
app = get_wsgi_application()
if __name__ == "__main__":
# Introduction of command line start mode function , Easy to start the test directly , Same as manage.py file
from django.core.management import execute_from_command_line

Run the following command directly to start the service :

python app.py runserver

You can also use uwsgi Wait for the application to start . If you use gunicorn as follows :

gunicorn app:app

I hope I can help you ~

added Django The test and build method of single file can go to Adam Johnson(Django Members of the Technical Committee , The British Django MeetUp The organizer of ) Of Blog Look up .


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